COMEDK · Physics · 3. Motion In One Dimension
A particle starts from rest and moves along the x -axis with a velocity that varies as \(\mathrm{v}=\sqrt{100+4 x} \mathrm{~ms}^{-1}\). The acceleration of the particle is:
- A \(2 m s^{-2}\)
- B \(5 m s^{-2}\)
- C \(25 \mathrm{~ms}^{-2}\)
- D \(4 m s^{-2}\)
Answer & Solution
Correct Answer
(A) \(2 m s^{-2}\)
Step-by-step Solution
Detailed explanation
Given the velocity \(v = \sqrt{100 + 4x}\). The acceleration \(a\) of a particle moving in one dimension is given by \(a = v \dfrac{dv}{dx}\). Differentiating \(v = (100 + 4x)^{1/2}\) with respect to \(x\):…
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