COMEDK · Physics · 17. Electrostatics
A particle of mass 3 g and charge \(60 \mu \mathrm{C}\) is released from rest in a uniform electric field of intensity \(10^5 N C^{-1}\). If the value of kinetic energy attained by the particle after moving through a distance of 2 cm is \(m \times 10^{-2} \mathrm{~J}\), then the value of m is:
- A \(5\)
- B \(4\)
- C \(6\)
- D \(12\)
Answer & Solution
Correct Answer
(D) \(12\)
Step-by-step Solution
Detailed explanation
Given mass \(m = 3 \text{ g} = 3 \times 10^{-3} \text{ kg}\), charge \(q = 60 \mu \text{C} = 60 \times 10^{-6} \text{ C}\), electric field \(E = 10^5 \text{ N C}^{-1}\), and distance \(d = 2 \text{ cm} = 0.02 \text{ m}\). The force acting on the particle is…
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