COMEDK · Physics · 27. Dual Nature of Matter
A particle of mass \(2 \mathrm{mg}\) has the same wavelength as a neutron moving with a velocity of \(3 \times 10^5 \mathrm{~ms}^{-1}\). The velocity of the particle is (mass of neutron is \(1.67 \times 10^{-27} \mathrm{Kg}\))
- A \(1.5 \times 10^{-13} \mathrm{~ms}^{-1}\)
- B \(2.5 \times 10^{-16} \mathrm{~ms}^{-1}\)
- C \(1.5 \times 10^{-16} \mathrm{~ms}^{-1}\)
- D \(2.5 \times 10^{-13} \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(B) \(2.5 \times 10^{-16} \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
The de Broglie wavelength \(\lambda\) is given by the relation \(\lambda = \dfrac{h}{mv}\). Since the particle and the neutron have the same wavelength, we have \(\lambda_{p} = \lambda_{n}\), which implies \(m_{p} v_{p} = m_{n} v_{n}\). Given values are: Mass of particle…
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