COMEDK · Physics · 9. Gravitation
A particle of mass 1 kg is kept on the surface of a uniform sphere of mass 20 kg and radius 1.0 m . The work to be done against the gravitational force between them to take the particle away from the sphere is
- A \(0.5 \times 10^{-9} \mathrm{~J}\)
- B \(1.334 \times 10^{-9} \mathrm{~J}\)
- C \(2532 \times 10^{-9} \mathrm{~J}\)
- D zero
Answer & Solution
Correct Answer
(B) \(1.334 \times 10^{-9} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Potential at the surface of earth, \(V=-\frac{G M}{R}\) \(\begin{aligned} & =-\frac{6.67 \times 10^{-11} \times 20}{1} \\ & =-1.334 \times 10^{-9} \mathrm{~J} / \mathrm{K} \end{aligned}\) i.e., \(1.334 \times 10^{-9} \mathrm{~J}\) work is done to bring a mass of 1 kg from…
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