COMEDK · Physics · 3. Motion In One Dimension

A particle moves towards west with a velocity of \(10 \mathrm{~ms}^{-1}\). After 10s its direction changes towards south and it moves with the same velocity. The average acceleration of the particle is:

A \(\sqrt{2} m s^{-2} S E\)
B \(2 \sqrt{2} m s^{-2} N E\)
C \(\left(\dfrac{1}{\sqrt{2}}\right) m s^{-2} S E\)
D \(2 m s^{-2} N E\)

Verified Solution

Answer & Solution

Correct Answer

(A) \(\sqrt{2} m s^{-2} S E\)

Step-by-step Solution

Detailed explanation

The initial velocity vector is \(\vec{v}_i = -10 \hat{i} \text{ m/s}\) (towards west). The final velocity vector is \(\vec{v}_f = -10 \hat{j} \text{ m/s}\) (towards south). The change in velocity is…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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