COMEDK · Physics · 3. Motion In One Dimension
A particle moves along a parabolic path \(y = 9x^2\) in such a way that the x component of velocity remains constant. If, the acceleration of the particle is \(2j\ ms^{-2}\), find the x component of velocity.
- A \(\dfrac{1}{9}\ ms^{-1}\)
- B \(\dfrac{1}{6}\ ms^{-1}\)
- C \(\dfrac{1}{3}\ ms^{-1}\)
- D \(\dfrac{1}{4}\ ms^{-1}\)
Answer & Solution
Correct Answer
(C) \(\dfrac{1}{3}\ ms^{-1}\)
Step-by-step Solution
Detailed explanation
The equation of the path is given by \(y = 9x^2\). Differentiating with respect to time \(t\), we get the y-component of velocity: \(v_y = \dfrac{dy}{dt} = 18x \dfrac{dx}{dt} = 18x v_x\) Differentiating again with respect to time \(t\), we get the y-component of acceleration:…
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