COMEDK · Physics · 15. Oscillations
A particle is performing simple harmonic motion. Equation of its motion is \(x=5 \sin \left(4 t-\dfrac{\pi}{6}\right), x\) being the displacement from mean position. Velocity (in \(\mathrm{ms}^{-1}\) ) of the particle at the instant when its displacement is 3 , will be
- A \(\dfrac{2 \pi}{3}\)
- B \(\dfrac{5 \pi}{6}\)
- C 20
- D 16
Answer & Solution
Correct Answer
(D) 16
Step-by-step Solution
Detailed explanation
The displacement equation is given by \(x = 5 \sin \left(4t - \dfrac{\pi}{6}\right)\). The velocity \(v\) of a particle in simple harmonic motion is given by \(v = \dfrac{dx}{dt} = 5 \times 4 \cos \left(4t - \dfrac{\pi}{6}\right) = 20 \cos \left(4t - \dfrac{\pi}{6}\right)\).…
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