COMEDK · Physics · 18. Capacitance
A parallel plate capacitor has a capacity \(C\). The separation between the plates is doubled and a dielectric medium is inserted between the plates. If the capacity is \(3 C\), then the dielectric constant of the medium will be
- A \(1.5\)
- B \(3\)
- C \(6\)
- D \(12\)
Answer & Solution
Correct Answer
(C) \(6\)
Step-by-step Solution
Detailed explanation
We know that, capacitance of a parallel plate capacitor, \[ C=\frac{\varepsilon_{0} A}{d} \] where, \(A=\) area of plate \(d=\) separation between the plates. When \(d^{\prime}=2 d\), then \(C^{\prime}=\frac{\varepsilon_{0} A K}{d^{\prime}}\)…
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