COMEDK · Physics · 26. Wave Optics
A parallel beam of monochromatic light of wavelength 800 nm passes through a single slit of 0.25 mm width. The angular divergence corresponding to the second order minima will be:
- A \(4.81 \times 10^{-3} \mathrm{rad}\)
- B \(12.8 \times 10^{-3} \mathrm{rad}\)
- C \(1.35 \times 10^{-3} \mathrm{rad}\)
- D \(2.18 \times 10^{-3} \mathrm{rad}\)
Answer & Solution
Correct Answer
(B) \(12.8 \times 10^{-3} \mathrm{rad}\)
Step-by-step Solution
Detailed explanation
For single slit diffraction, the \(n\)-th order minimum occurs at \(a\sin\theta = n\lambda\). For small angles, \(\theta = \dfrac{n\lambda}{a}\). Angular divergence = total spread between second-order minima on both sides \(= 2\theta = \dfrac{2n\lambda}{a}\)…
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