COMEDK · Physics · 12. Thermal Properties of Matter
A one \(\mathrm{kg}\) block of ice at \(-1.5^{\circ} \mathrm{C}\) falls from a height of \(1.5 \mathrm{~km}\) and is found melting. The amount of ice melted due to fall, if \(60 \%\) energy is converted into heat is (Specific heat capacity of ice is \(0.5 \mathrm{~cal} \mathrm{~g}^{-1} \mathrm{~C}^{-1}\), Latent heat of fusion of ice \(=80 \mathrm{~cal~g}^{-1}\) )
- A 17.9 g
- B 16.9 g
- C 10 g
- D 1.69 g
Answer & Solution
Correct Answer
(B) 16.9 g
Step-by-step Solution
Detailed explanation
PE lost \(= mgh = 1 \times 9.8 \times 1500 = 14700\) J Heat generated \(= 0.6 \times 14700 = 8820\) J \(= \dfrac{8820}{4.2} = 2100\) cal Heat to warm ice from \(-1.5°C\) to \(0°C\): \(Q_1 = 1000 \times 0.5 \times 1.5 = 750\) cal Heat available for melting:…
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