COMEDK · Physics · 17. Electrostatics
A neutral water molecule, modeled as an electric dipole with an effective charge equal to one elementary charge (\(e = 1.6 \times 10^{-19} \text{ C}\)), is placed in an electric field \(E = 2.5 \times 10^4 \text{ NC}^{-1}\). The work done to rotate it by \(180^\circ\) from its stable equilibrium position is \(5 \times 10^{-25} \text{ J}\). Find the approximate separation of the centre of charges.
- A \(0.625 \times 10^{-9} \mathrm{~m}\)
- B \(0.625 \times 10^{-10} \mathrm{~m}\)
- C \(1.25 \times 10^{-10} \mathrm{~m}\)
- D \(0.998 \times 10^{-10} \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(0.625 \times 10^{-10} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Work done to rotate dipole by \(180°\) from stable equilibrium: \(W = pE(\cos 0° - \cos 180°) = 2pE\) \(p = \dfrac{W}{2E} = \dfrac{5 \times 10^{-25}}{2 \times 2.5 \times 10^4} = \dfrac{5 \times 10^{-25}}{5 \times 10^4} = 10^{-29}\) C m…
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