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COMEDK · Physics · 17. Electrostatics

A neutral water molecule, modeled as an electric dipole with an effective charge equal to one elementary charge (\(e = 1.6 \times 10^{-19} \text{ C}\)), is placed in an electric field \(E = 2.5 \times 10^4 \text{ NC}^{-1}\). The work done to rotate it by \(180^\circ\) from its stable equilibrium position is \(5 \times 10^{-25} \text{ J}\). Find the approximate separation of the centre of charges.

  1. A \(0.625 \times 10^{-9} \mathrm{~m}\)
  2. B \(0.625 \times 10^{-10} \mathrm{~m}\)
  3. C \(1.25 \times 10^{-10} \mathrm{~m}\)
  4. D \(0.998 \times 10^{-10} \mathrm{~m}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(0.625 \times 10^{-10} \mathrm{~m}\)

Step-by-step Solution

Detailed explanation

Work done to rotate dipole by \(180°\) from stable equilibrium: \(W = pE(\cos 0° - \cos 180°) = 2pE\) \(p = \dfrac{W}{2E} = \dfrac{5 \times 10^{-25}}{2 \times 2.5 \times 10^4} = \dfrac{5 \times 10^{-25}}{5 \times 10^4} = 10^{-29}\) C m…