COMEDK · Physics · 22. Electromagnetic Induction
A metallic rod of length '\(a\)' is rotated with an angular frequency of \(0.2 \mathrm{~rads}^{-1}\) about an axis normal to the rod passing through its one end. A constant and uniform magnetic field of '\(\mathrm{B}\)' T parallel to the axis exists everywhere. The emf developed across the ends of the rod is
- A \(\dfrac{\mathrm{Ba}^2}{10}\)
- B \(\dfrac{\mathrm{Ba}^2}{2}\)
- C \(\dfrac{\mathrm{Ba}^2}{50}\)
- D \(\dfrac{\mathrm{Ba}^2}{5}\)
Answer & Solution
Correct Answer
(A) \(\dfrac{\mathrm{Ba}^2}{10}\)
Step-by-step Solution
Detailed explanation
The motional electromotive force (emf) induced in a rod of length \(a\) rotating with angular velocity \(\omega\) in a uniform magnetic field \(B\) perpendicular to the plane of rotation is given by the integral of \(d\epsilon = B v dr\), where \(v = \omega r\). The emf \(E\) is…
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