COMEDK · Physics · 22. Electromagnetic Induction
A metallic rod of \(2 \mathrm{~m}\) length is rotated with a frequency \(100 \mathrm{~Hz}\) about an axis passing through the centre of the circular ring of radius \(2 \mathrm{~m}\). A constant magnetic field \(2 \mathrm{~T}\) is applied parallel to the axis and perpendicular to the length of the rod. The emf developed across the ends of the rod is :
- A 800 \(\pi\) volt
- B 400 \(\pi\) volt
- C 1600 \(\pi\) volt
- D 1600 volt
Answer & Solution
Correct Answer
(A) 800 \(\pi\) volt
Step-by-step Solution
Detailed explanation
The induced emf \(e\) across a rod of length \(l\) rotating with angular velocity \(\omega\) in a uniform magnetic field \(B\) perpendicular to the plane of rotation is given by the formula \(e = \dfrac{1}{2} B \omega l^2\). Given parameters are: Length of the rod…
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