COMEDK · Physics · 5. Laws of Motion
A mass of \(10 \mathrm{~kg}\) is suspended from a spring balance. It is pulled a side by a horizontal string, so that it makes an angle of \(60^{\circ}\) with the vertical. The new reading of the balance is
- A \(20 \mathrm{~kg}\)-wt
- B \(10 \mathrm{~kg}-\mathrm{wt}\)
- C \(10 \sqrt{3} \mathrm{~kg}\)-wt
- D \(20 \sqrt{3} \mathrm{~kg}-\mathrm{wt}\)
Answer & Solution
Correct Answer
(A) \(20 \mathrm{~kg}\)-wt
Step-by-step Solution
Detailed explanation
Given, mass suspended from spring balance, \(m=10 \mathrm{~kg}\) \[ \theta=60^{\circ} \] The given situation is shown below From the diagram, reading of spring balance, \(F_{s}=T\) Since, \(T \cos \theta=m g\) \[ T=\frac{m g}{\cos \theta} \] From Eqs, (i) and (ii) we get…
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