COMEDK · Physics · 15. Oscillations
A mass \(M\) is suspended from a light spring. An additional mass \(m\) added displaces the spring further by a distance \(X\). Now, the combined mass will oscillate on the spring with period
- A \(T=2 \pi \sqrt{\frac{m g}{X(M+m)}}\)
- B \(T=2 \pi \sqrt{\frac{(M+m) X}{m g}}\)
- C \(T=\frac{\pi}{2} \sqrt{\frac{m g}{X(M+m)}}\)
- D \(T=2 \pi \sqrt{\frac{(M+m)}{m g}}\)
Answer & Solution
Correct Answer
(B) \(T=2 \pi \sqrt{\frac{(M+m) X}{m g}}\)
Step-by-step Solution
Detailed explanation
At initial condition of spring, \[ M g=k X_{0} \quad \text{...(i)} \] When mass \(m\) is added, then at equilibrium, \((M+m) g=k\left(X+X_{0}\right)\) \(\Rightarrow M g+m g=k X+k X_{0}\) \(\Rightarrow M g+m g=k X+M g \quad \text{[from Eq. (i)]}\) \(\Rightarrow \quad m g=k X\)…
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