COMEDK · Physics · 16. Waves and Sound
A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one secon(d)If the speed of sound in air is \(340 \mathrm{~ms}^{-1}\), then the distance between the cliffs, is
- A \(340 \mathrm{~m}\)
- B \(1620 \mathrm{~m}\)
- C \(680 \mathrm{~m}\)
- D \(1700 \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(340 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Given, time interval between echoes \(=1 \mathrm{~s}\) Speed of sound in air, \(v=340 \mathrm{~ms}^{-1}\) Let the distance between man and cliff be \(x\). Time taken by sound to hit cliff and return \(=\frac{2 x}{v}\)…
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