COMEDK · Physics · 3. Motion In One Dimension
A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is \(340 \mathrm{~ms}^{-1}\), then the distance between the cliffs is
- A \(680 \mathrm{~m}\)
- B \(1700 \mathrm{~m}\)
- C \(340 \mathrm{~m}\)
- D \(1620 \mathrm{~m}\)
Answer & Solution
Correct Answer
(C) \(340 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Let \(x\) be the distance between a cliff and man, then time taken by the echo, \[ \begin{aligned} t &=\frac{2 x}{v}=1 \\ \Rightarrow \quad x &=\frac{v}{2}=\frac{340}{2}=170 \mathrm{~m} \end{aligned} \] (given) \(\therefore\) Distance between two cliffs…
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