COMEDK · Physics · 7. Center of Mass Momentum and Collision
A machine gun fires a bullet of mass m with a velocity of 1000 m/min. The man holding the gun can exert a force of 200 N on the gun. The product of mass of each bullet and the number of bullets fired in one sec is
- A \(5\)
- B \(12\)
- C \(24\)
- D \(6\)
Answer & Solution
Correct Answer
(B) \(12\)
Step-by-step Solution
Detailed explanation
Velocity of the bullet, \(v = 1000 \text{ m/min} = \dfrac{1000}{60} \text{ m/s} = \dfrac{50}{3} \text{ m/s}\) Force exerted by the man, \(F = 200 \text{ N}\) The force required to hold the gun is equal to the rate of change of momentum of the bullets. \(F = n \cdot m \cdot v\)…
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