COMEDK · Physics · 6. Work Power Energy
A long spring, when stretched by a distance \(x\), has potential energy \(U\). On increasing the stretching to \(n x\), the potential energy of the spring will be
- A \(\frac{U}{n}\)
- B \(n U\)
- C \(n^2 U\)
- D \(\frac{U}{n^2}\)
Answer & Solution
Correct Answer
(C) \(n^2 U\)
Step-by-step Solution
Detailed explanation
Potential energy of the spring, and \(U^{\prime}=\frac{1}{2} k(n x)^2 \Rightarrow U^{\prime}=n^2 \frac{1}{2} k x^2\) \(\Rightarrow \quad U^{\prime}=n^2 U \quad \text{[From Eq. (i)]}\)
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