COMEDK · Physics · 6. Work Power Energy
A long spring, when stretched by a distance \(x\), has potential energy \(U\). On increasing the stretching to \(n x\), the potential energy of the spring will be
- A \(\dfrac{U}{n}\)
- B \(n^2 U\)
- C \(\dfrac{U}{n^2}\)
- D \(nU\)
Answer & Solution
Correct Answer
(B) \(n^2 U\)
Step-by-step Solution
Detailed explanation
The potential energy \(U\) stored in a spring stretched by a distance \(x\) is given by the formula \(U = \dfrac{1}{2} k x^{2}\), where \(k\) is the spring constant. When the stretching is increased to \(n x\), the new potential energy \(U'\) is given by…
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