COMEDK · Physics · 22. Electromagnetic Induction
A long solenoid has 400 turns. When a current of 100 A is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 mWb . The self-inductance of the solenoid is
- A 0.16 mH
- B 16 mH
- C 16 H
- D 1.6 mH
Answer & Solution
Correct Answer
(B) 16 mH
Step-by-step Solution
Detailed explanation
The self-inductance \(L\) of a solenoid is defined by the relation \(\Phi_{total} = L I\), where \(\Phi_{total}\) is the total magnetic flux linked with all turns of the solenoid. Given the number of turns \(N = 400\), the current \(I = 100\) A, and the magnetic flux linked with…
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