COMEDK · Physics · 11. Mechanical Properties of Fluids
A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg . The area of cross-section of the piston carrying the board is \(425 \mathrm{~cm}^2\). What maximum pressure would smaller piston have to bear?
- A \(5.2 \times 10^4 \mathrm{~Pa}\)
- B \(4.2 \times 10^5 \mathrm{~Pa}\)
- C \(6.92 \times 10^4 \mathrm{~Pa}\)
- D \(5.92 \times 10^5 \mathrm{~Pa}\)
Answer & Solution
Correct Answer
(C) \(6.92 \times 10^4 \mathrm{~Pa}\)
Step-by-step Solution
Detailed explanation
The maximum force, which the bigger piston can bear, \(F=30000 \mathrm{kgf}=3000 \times 9.8 \mathrm{~N}\) Area of piston, \(A=425 \mathrm{~cm}^2=425 \times 10^{-4} \mathrm{~m}^2\) \(\therefore\) Maximum pressure on the bigger piston,…
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