COMEDK · Physics · 4. Motion In Two Dimensions
A hockey player hits the ball at an angle of \(37^{\circ}\) from the horizontal with an initial speed of \(40 \mathrm{~m} / \mathrm{s}\) (a right angled triangle with one of the angle is \(37^{\circ}\) and their sides in the ratio of \(6: 8: 10\)). Assume that the ball is in a vertical plane. The time at which the ball reaches the highest point of its path is
- A 3.2 s
- B 2.4 s
- C 0.32 s
- D 0.24 s
Answer & Solution
Correct Answer
(B) 2.4 s
Step-by-step Solution
Detailed explanation
The initial velocity of the ball is \(u = 40 \text{ m/s}\) and the angle of projection is \(\theta = 37^{\circ}\). The vertical component of the initial velocity is given by \(u_y = u \sin \theta\). Given the triangle with sides in ratio \(3:4:5\) (which is equivalent to…
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