COMEDK · Physics · 12. Thermal Properties of Matter
A glass of hot water cools from \(90^{\circ} \mathrm{C}\) to \(70^{\circ} \mathrm{C}\) in 3 minutes when the temperature of surroundings is \(20^{\circ} \mathrm{C}\). What is the time taken by the glass of hot water to cool from \(60^{\circ} \mathrm{C}\) to \(40^{\circ} \mathrm{C}\) if the surrounding temperature remains the same at \(20^{\circ} \mathrm{C}\) ?
- A 15 minutes
- B 6 minutes
- C 12 minutes
- D 10 minutes
Answer & Solution
Correct Answer
(B) 6 minutes
Step-by-step Solution
Detailed explanation
According to Newton's law of cooling, the rate of cooling is given by \(\dfrac{dT}{dt} = -k(T - T_s)\), where \(T\) is the temperature of the body, \(T_s\) is the temperature of the surroundings, and \(k\) is a constant. For the first interval, \(T_1 = 90^{\circ} \text{C}\),…
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