COMEDK · Physics · 14. Kinetic Theory of Gases
A gaseous mixture consists of \(16 \mathrm{~g}\) of helium and \(16 \mathrm{~g}\) of oxygen. The ratio \(C_{p} / C_{V}\) of the mixture is
- A \(1.4\)
- B \(1.54\)
- C \(1.59\)
- D \(1.62\)
Answer & Solution
Correct Answer
(D) \(1.62\)
Step-by-step Solution
Detailed explanation
Mass of helium, \(m_{1}=16 \mathrm{~g}\) Mass of oxygen, \(m_{2}=16 \mathrm{~g}\) \(\therefore\) Number of moles of He gas, \[ n_{1}=\frac{m_{1}}{4}=\frac{16}{4}=4 \] Number of moles of \(\mathrm{O}_{2} \mathrm{gas}\), \[ n_{2}=\frac{m_{2}}{32}=\frac{16}{32}=\frac{1}{2} \] We…
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