COMEDK · Physics · 21. Magnetic Effects of Current
A galvanometer having a resistance of \(8 \Omega\) is shunted by a wire of resistance \(2 \Omega\). If the total current is \(1 \mathrm{~A}\), the part of it passing through the shunt will be
- A \(0.25 \mathrm{~A}\)
- B \(0.8 \mathrm{~A}\)
- C \(0.2 \mathrm{~A}\)
- D \(0.5 \mathrm{~A}\)
Answer & Solution
Correct Answer
(B) \(0.8 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Let total current through the parallel combination be \(I\), the current through the galvanometer be \(I_g\) and the current through the shunt be \(I-I_g\). The shunted galvanometer is shown in the figure. The potential difference, \(V_{a b}=\left(V_a-V_b\right)\) is the same…
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