COMEDK · Physics · 19. Current Electricity
A galvanometer having a resistance of \(50 \Omega\) is shunted by a wire of resistance \(10 \Omega\). If the total current is 2 A , the current passing through the shunt is:
- A \(\dfrac{5}{3} \mathrm{~A}\)
- B \(\dfrac{3}{5} \mathrm{~A}\)
- C \(\dfrac{5}{6} \mathrm{~A}\)
- D \(\dfrac{2}{5} \mathrm{~A}\)
Answer & Solution
Correct Answer
(A) \(\dfrac{5}{3} \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Let \(G\) be the resistance of the galvanometer and \(S\) be the resistance of the shunt wire. Given \(G = 50 \Omega\) and \(S = 10 \Omega\). The total current \(I = 2 \text{ A}\). The current \(I_S\) passing through the shunt is given by the current divider rule:…
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