COMEDK · Physics · 19. Current Electricity
A galvanometer having a resistance of \(4 \Omega\) is shunted by a wire of resistance \(2 \Omega\). If the total current is \(1.5 \mathrm{~A}\), the current passing through shunt is
- A \(1.25 \mathrm{~A}\)
- B \(1 \mathrm{~A}\)
- C \(0.75 \mathrm{~A}\)
- D \(0.5 \mathrm{~A}\)
Answer & Solution
Correct Answer
(B) \(1 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Let \(G\) be the resistance of the galvanometer and \(S\) be the resistance of the shunt. Given \(G = 4 \Omega\) and \(S = 2 \Omega\). The total current \(I = 1.5 \mathrm{~A}\) divides into the galvanometer current \(I_g\) and the shunt current \(I_s\) such that…
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