COMEDK · Physics · 25. Ray Optics
A fish in water (refractive index \(n\) ) looks at a bird vertically above in the air. If \(y\) is the height of the bird and \(x\) is the depth of the fish from the surface, then the distance of the bird as estimated by the fish is
- A \(x+y\left(1-\frac{1}{n}\right)\)
- B \(x+n y\)
- C \(x+y\left(1+\frac{1}{n}\right)\)
- D \(y+x\left(1-\frac{1}{n}\right)\)
Answer & Solution
Correct Answer
(B) \(x+n y\)
Step-by-step Solution
Detailed explanation
Refractive index of water \(=n\) Since, fish looks the bird from water (denser medium) to air (rarer medium). Hence, normal shift \(d=(n-1) h\) But according to question, real depth \(h=y\)…
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