COMEDK · Physics · 26. Wave Optics

A diffraction pattern due to a single slit of width 0.12mm is obtained with a blue green light of wavelength 500 nm. The angular separation between central maximum and second order secondary maximum of the diffraction pattern is

A \(0.042 \times 10^{-3}\ rad\)
B \(1.042 \times 10^{-4}\ rad\)
C \(0.042 \times 10^{-2}\ rad\)
D \(1.042 \times 10^{-2}\ rad\)

Verified Solution

Answer & Solution

Correct Answer

(D) \(1.042 \times 10^{-2}\ rad\)

Step-by-step Solution

Detailed explanation

Given slit width, \(a = 0.12 \text{ mm} = 1.2 \times 10^{-4} \text{ m}\) Wavelength of light, \(\lambda = 500 \text{ nm} = 5 \times 10^{-7} \text{ m}\) The angular position of the \(n\)-th secondary maximum in a single slit diffraction pattern is given by:…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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