COMEDK · Physics · 18. Capacitance
A dielectric of dielectric constant \(K\) is introduced such that half of its area of a capacitor of capacitance \(C\) is occupied by it. The new capacity is
- A \(2 C\)
- B \(\frac{C}{2}\)
- C \(\frac{(1+K) C}{2}\)
- D \(2 C(1+K)\)
Answer & Solution
Correct Answer
(C) \(\frac{(1+K) C}{2}\)
Step-by-step Solution
Detailed explanation
The dielectric is introduced such that half of its area is occupied by it. In the given case, the two capacitors are in parallel. \(\therefore \quad C^{\prime}=C_1+C_2\) But \(\quad C_1=\frac{A \varepsilon_0}{2 d}\) and \(C_2=\frac{K A \varepsilon_0}{2 d}\) Thus,…
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