COMEDK · Physics · 18. Capacitance
A dielectric of dielectric constant \(K\) is introduced such that half of its area of a capacitor of capacitance \(C\) is occupied by it. The new capacity is
- A \(2 C(1+K)\)
- B \(2 C\)
- C \(\dfrac{(1+K) C}{2}\)
- D \(\dfrac{C}{2}\)
Answer & Solution
Correct Answer
(C) \(\dfrac{(1+K) C}{2}\)
Step-by-step Solution
Detailed explanation
The initial capacitance of the parallel plate capacitor is \(C = \dfrac{\epsilon_0 A}{d}\), where \(A\) is the area of the plates and \(d\) is the distance between them. When a dielectric of dielectric constant \(K\) is introduced such that it occupies half the area, the…
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