COMEDK · Physics · 11. Mechanical Properties of Fluids
A cylindrical tank 0.5 m in radius, rests on a platform 1.5 m high. Initially the tank is filled with water to a height of 2.5 m. A small plug whose area is \(10^{-4} \text{ m}^2\) is removed from an orifice located on the side of the tank at the bottom. The vertical speed with which the water strikes the ground is: [Assume \(g = 10 \text{ ms}^{-2}\)]
- A \(5.47 m s^{-1}\)
- B \(7.07 \mathrm{~ms}^{-1}\)
- C \(5.1 m s^{-1}\)
- D \(7.62 m s^{-1}\)
Answer & Solution
Correct Answer
(A) \(5.47 m s^{-1}\)
Step-by-step Solution
Detailed explanation
The orifice is on the side at the bottom, so water emerges horizontally with zero initial vertical velocity. The platform height \(H = 1.5\) m, so water falls 1.5 m vertically. \(v_y^2 = u_y^2 + 2gH = 0 + 2 \times 10 \times 1.5 = 30\) \(v_y = \sqrt{30} \approx 5.47 \ ms^{-1}\)
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