COMEDK · Physics · 21. Magnetic Effects of Current
A current loop consists of two identical semicircular parts each of radius \(2 R\), one lying in the \(x-y\) plane and the other in \(x-z\) plane. If the current in the loop is \(I\), the resultant magnetic field due to two semicircular parts at their common centre is
- A \(\dfrac{\mu_o I}{4 R}\)
- B \(\dfrac{\mu_o I}{\sqrt{2} R}\)
- C \(\dfrac{\mu_o I}{4 \sqrt{2} R}\)
- D \(\dfrac{4 \mu_o I}{\sqrt{2} R}\)
Answer & Solution
Correct Answer
(C) \(\dfrac{\mu_o I}{4 \sqrt{2} R}\)
Step-by-step Solution
Detailed explanation
The magnetic field at the center of a semicircular loop of radius \(r\) carrying current \(I\) is given by \(B = \dfrac{\mu_0 I}{4r}\). In this problem, the radius of each semicircular part is \(2R\). Therefore, the magnitude of the magnetic field due to each semicircular part…
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