COMEDK · Physics · 21. Magnetic Effects of Current
A current carrying closed loop in the form of a right isosceles triangle XYZ is placed in a uniform magnetic field \(B\) acting along \(X Y\) of the loop. If the magnetic force on the \(\operatorname{arm} Y Z\) is \(\sqrt{2} F\), then the force on the arm \(X Z\) is:

- A \(-F\)
- B \(-\sqrt{2} F\)
- C \(+2 \sqrt{2} F\)
- D \(\dfrac{F}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(B) \(-\sqrt{2} F\)
Step-by-step Solution
Detailed explanation
The net magnetic force on a closed current-carrying loop in a uniform field is zero: \(\vec{F}_{XY} + \vec{F}_{YZ} + \vec{F}_{XZ} = 0\) Since field \(B\) acts along arm \(XY\), the arm \(XY\) is parallel to \(\vec{B}\), so \(\vec{F}_{XY} = 0\). Therefore:…
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