COMEDK · Physics · 14. Kinetic Theory of Gases
A cubical box of side \(2 \mathrm{~m}\) contains helium gas. It was observed that in a time of 1 second, an atom travelling with the root-mean-square speed parallel to one of the edges of the cube, made 250 hits with one of the walls, without any collision with other atoms. The average kinetic energy of the helium gas is Take \(R=\dfrac{25}{3} \mathrm{~J} / \mathrm{mol}-\mathrm{K}\) and \(\mathrm{kB}=1.38 \times 10^{-23} \mathrm{JK}{ }^{-1}\)
- A \(3.31 \times 10^{-21} \mathrm{~J}\)
- B \(82.8 \times 10^{-21} \mathrm{~J}\)
- C \(1 \times 10^{-21} \mathrm{~J}\)
- D \(82.8 \times 10^{-19} \mathrm{~J}\)
Answer & Solution
Correct Answer
(A) \(3.31 \times 10^{-21} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
The side length of the cubical box is \(L = 2 \text{ m}\). An atom travelling with root-mean-square speed \(v_{rms}\) parallel to one of the edges makes 250 hits in 1 second. The distance covered by the atom between two consecutive hits on the same wall is \(2L\). The time taken…
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