COMEDK · Physics · 4. Motion In Two Dimensions
A cricketer of height \(2.5 \mathrm{~m}\) throws a ball at an angle of \(30^{\circ}\) with the horizontal such that it is received by another cricketer of same height standing at a distance of \(50 \mathrm{~m}\) from the first one. The maximum height attained by the ball is (\(\tan 30^{\circ}=0.577\))
- A 9.7 m
- B 7.9 m
- C 10.7 m
- D 10 m
Answer & Solution
Correct Answer
(A) 9.7 m
Step-by-step Solution
Detailed explanation
The height of both cricketers is \(h = 2.5 \text{ m}\). Since the ball is thrown and received at the same height, the vertical displacement is zero. The horizontal range \(R\) is given by \(R = \dfrac{u^2 \sin(2\theta)}{g}\). Given \(R = 50 \text{ m}\) and…
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