COMEDK · Physics · 9. Gravitation
A constant potential energy of a satellite is given as
\[
\mathrm{PE}=r(\mathrm{KE})
\]
where, \(\mathrm{PE}=\) potential energy
and \(\mathrm{KE}=\) kinetic energy.
The value of \(r\) will be
- A \(-1\)
- B \(-2\)
- C \(\dfrac{-1}{2}\)
- D \(\dfrac{-3}{2}\)
Answer & Solution
Correct Answer
(B) \(-2\)
Step-by-step Solution
Detailed explanation
For a satellite orbiting a planet of mass \(M\) at a distance \(R\) with orbital speed \(v\), the gravitational potential energy is given by \(PE = -\dfrac{GMm}{R}\). The kinetic energy of the satellite is given by \(KE = \dfrac{1}{2}mv^2\). Since the centripetal force is…
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