COMEDK · Physics · 22. Electromagnetic Induction
A coil of wire of a certain radius has 100 turns and a self inductance of \(15 \mathrm{mH}\). The self inductance of a second similar coil of 500 turns will be
- A \(75 \mathrm{mH}\)
- B \(375 \mathrm{mH}\)
- C \(15 \mathrm{mH}\)
- D None of the above
Answer & Solution
Correct Answer
(B) \(375 \mathrm{mH}\)
Step-by-step Solution
Detailed explanation
Given, number of turns in the first ood, \(N_{1}=100\) Its self-indioctanee, \(L_{\mathrm{t}}=15 \mathrm{mII}=15 \times 10^{-2} \mathrm{11}\) Number of turns in the socond eodl. \[ N_{2}=500 \] \[ \therefore \quad \mathrm{Leg}^{2}=\text { ? } \] We know that, self inductance of…
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