COMEDK · Physics · 23. Alternating Current
A coil of inductance \(1 \mathrm{H}\) and resistance \(100 \Omega\) is connected to an alternating current source of frequency \(\dfrac{50}{\pi} \mathrm{~Hz}\). What will be the phase difference between the current and voltage?
- A 90\(^\circ\)
- B 60\(^\circ\)
- C 30\(^\circ\)
- D 45\(^\circ\)
Answer & Solution
Correct Answer
(D) 45\(^\circ\)
Step-by-step Solution
Detailed explanation
Given inductance \(L = 1 \text{ H}\), resistance \(R = 100 \Omega\), and frequency \(f = \dfrac{50}{\pi} \text{ Hz}\). The angular frequency \(\omega\) is given by \(\omega = 2 \pi f = 2 \pi \times \dfrac{50}{\pi} = 100 \text{ rad/s}\). The inductive reactance \(X_L\) is given…
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