COMEDK · Physics · 21. Magnetic Effects of Current
A circular coil of radius \(0.1 \mathrm{~m}\) is placed in the \(\mathrm{X}-\mathrm{Y}\) plane and a current \(2 \mathrm{~A}\) is passed through the coil in the clockwise direction when looking from above. Find the magnetic dipole moment of the current loop
- A \(0.02 \pi \mathrm{Am}^2 \text { in the }+ \text { ve } \mathrm{Z}-\text { direction }\)
- B \(0.02 \pi \mathrm{Am}^2 \text { in the }+ \text { ve } \mathrm{Y}-\text { direction }\)
- C \(0.02 \pi \mathrm{Am}^2 \text { in the -ve } \mathrm{X} \text { - direction }\)
- D \(0.02 \pi \mathrm{Am}^2 \text { in the }-\mathrm{ve} \mathrm{~Z}-\text { direction }\)
Answer & Solution
Correct Answer
(D) \(0.02 \pi \mathrm{Am}^2 \text { in the }-\mathrm{ve} \mathrm{~Z}-\text { direction }\)
Step-by-step Solution
Detailed explanation
The magnetic dipole moment \(\vec{m}\) of a current loop is given by the formula \(\vec{m} = I \vec{A}\), where \(I\) is the current and \(\vec{A}\) is the area vector. The radius of the coil is \(r = 0.1 \text{ m}\). The area of the circular coil is…
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