COMEDK · Physics · 22. Electromagnetic Induction
A circular coil of area \(2 \sqrt{2} \mathrm{~cm}^2\) and resistance \(2 \boldsymbol{\Omega}\) is arranged vertically in the east -west direction. A uniform magnetic field 0.2 T is set up across the plane in the north to east direction. Now the magnetic field is removed at a steady rate in 0.4 s What is the current developed in the coil?
- A \(1 \times 10^{-4} A\)
- B \(0.5 \times 10^{-5} \mathrm{~A}\)
- C \(0.5 \times 10^{-3} A\)
- D \(0.5 \times 10^{-4} A\)
Answer & Solution
Correct Answer
(D) \(0.5 \times 10^{-4} A\)
Step-by-step Solution
Detailed explanation
The area of the coil is \(A = 2 \sqrt{2} \text{ cm}^2 = 2 \sqrt{2} \times 10^{-4} \text{ m}^2\). The magnetic field \(B = 0.2 \text{ T}\) is in the north-east direction, while the coil is in the east-west plane. The normal to the coil points in the north-south direction. The…
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