COMEDK · Physics · 17. Electrostatics
A charge of \(0.8 \mathrm{C}\) is divided into two charges \(Q_{1}\) and \(Q_{2}\). These are kept at a separation of \(30 \mathrm{~cm}\). The force on \(Q_{1}\) is maximum when
- A \(Q_{1}=Q_{2}=0.4 \mathrm{C}\)
- B \(Q_{1} \approx 0.8 \mathrm{C}, Q_{2}\) negligible
- C \(Q_{1}\) negligible, \(Q_{2} \approx 0.8 \mathrm{C}\)
- D \(Q_{1}=0.2 \mathrm{C}, Q_{2}=0.6 \mathrm{C}\)
Answer & Solution
Correct Answer
(A) \(Q_{1}=Q_{2}=0.4 \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Given, \(Q_{1}+Q_{2}=0.8 \mathrm{C}\) \[ r \approx 30 \mathrm{~cm}=0.3 \mathrm{~m} \] \(\therefore\) According to Coulomb's law \[ \begin{aligned} &F=k \frac{Q_{1} Q_{2}}{r^{2}} \\ &F=k \frac{Q_{1}\left(0.8-Q_{1}\right)}{r^{2}} \end{aligned} \]…
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