COMEDK · Physics · 18. Capacitance
A capacitor of capacity \(2 \mu \mathrm{F}\) is charged upto a potential \(14 \mathrm{~V}\) and then connected in parallel to an uncharged capacitor of capacity \(5 \mu \mathrm{F}\). The final potential difference across each capacitor will be
- A \(6 \mathrm{~V}\)
- B \(4 \mathrm{~V}\)
- C \(8 \mathrm{~V}\)
- D \(14 \mathrm{~V}\)
Answer & Solution
Correct Answer
(B) \(4 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
When two capacitors are connected then their common potential difference is…
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