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COMEDK · Physics · 18. Capacitance

A capacitor of capacity \(2 ~\mu \mathrm{F}\) is charged upto a potential \(14 \mathrm{~V}\) and then connected in parallel to an uncharged capacitor of capacity \(5 ~\mu \mathrm{F}\). The final potential difference across each capacitor will be

  1. A 6 V
  2. B 4 V
  3. C 14 V
  4. D 8 V
Verified Solution

Answer & Solution

Correct Answer

(B) 4 V

Step-by-step Solution

Detailed explanation

The initial charge \(Q\) on the first capacitor is given by \(Q = C_1 V_1\). \(Q = 2 \mu \text{F} \times 14 \text{V} = 28 \mu \text{C}\). When the two capacitors are connected in parallel, the total charge \(Q\) is conserved and is shared between the two capacitors. Let \(V\) be…