COMEDK · Physics · 18. Capacitance
A capacitor of \(10 \mu \mathrm{F}\) is connected to a \(10 \mathrm{~V}\) cell. The maximum charge on the capacitor will be
- A \(1 \mu \mathrm{C}\)
- B \(10 \mu C\)
- C \(100 \mu \mathrm{C}\)
- D \(1000 \mu \mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(100 \mu \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Given, \(C=10 \mu \mathrm{F}=10 \times 10^{-6} \mathrm{~F}\) \(V=10 \mathrm{~V}\) \(\begin{aligned} \text{Change,} \quad q &=C \times V=10 \times 10^{-6} \times 10 \\ &=10^{-4} \mathrm{C} \\ &=100 \times 10^{6} \mathrm{C} \\ &=100 \mu \mathrm{C} \end{aligned}\)
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