COMEDK · Physics · 7. Center of Mass Momentum and Collision
A bullet of 0.02 kg moving with a speed of \(100 \mathrm{~ms}^{-1}\) hits a surface and comes to rest in 0.1 s What is the magnitude of the impulse of the force?
- A 10 N.s
- B 100 N.s
- C 2 N.s
- D 0.2 N.s
Answer & Solution
Correct Answer
(C) 2 N.s
Step-by-step Solution
Detailed explanation
The impulse \(J\) is defined as the change in linear momentum of the object. \(J = \Delta p = m(v_f - v_i)\) Given mass \(m = 0.02 \text{ kg}\), initial velocity \(v_i = 100 \text{ ms}^{-1}\), and final velocity \(v_f = 0 \text{ ms}^{-1}\) (since the bullet comes to rest).…
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