COMEDK · Physics · 23. Alternating Current
A bulb of resistance 280 Ohm is supplied with a voltage \(\mathrm{V}=400 \sin \pi \mathrm{t}\). The peak current is
- A 2.02 A
- B 2.22 A
- C 1.43 A
- D 1.11 A
Answer & Solution
Correct Answer
(C) 1.43 A
Step-by-step Solution
Detailed explanation
The given voltage is \(V = 400 \sin(\pi t)\). Comparing this with the standard form \(V = V_{peak} \sin(\omega t)\), the peak voltage is \(V_{peak} = 400\) V. The resistance of the bulb is \(R = 280\) Ohm. Using Ohm's law for the peak values, the peak current \(I_{peak}\) is…
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