COMEDK · Physics · 4. Motion In Two Dimensions
A boy is running along a straight horizontal road with a constant speed \(5 \mathrm{~ms}^{-1}\). While running he throws a stone with a velocity \(30 \mathrm{~ms}^{-1}\) at an angle \(60^{\circ}\) with the horizontal. Then the time of flight of the stone is: (Given \(g=10 \mathrm{~ms}^{-2}\) )
- A \(3 \sqrt{3}\)
- B \(3 \sqrt{2}\)
- C \(4 \sqrt{3}\)
- D \(\dfrac{\sqrt{3}}{2}\)
Answer & Solution
Correct Answer
(A) \(3 \sqrt{3}\)
Step-by-step Solution
Detailed explanation
The velocity of the stone is given with respect to the boy. Let the velocity of the boy be \(\vec{v}_b = 5 \hat{i} \text{ ms}^{-1}\). The velocity of the stone with respect to the boy is \(\vec{v}_{s/b} = 30 \cos 60^{\circ} \hat{i} + 30 \sin 60^{\circ} \hat{j} \text{ ms}^{-1}\).…
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