COMEDK · Physics · 5. Laws of Motion
A body of mass 125 kg just slides down a rough inclined plane that rises 1 m in every 2 m. What is the angle of friction?
- A \(\dfrac{\pi}{5}\)
- B \(\dfrac{\pi}{3}\)
- C \(\dfrac{\pi}{8}\)
- D \(\dfrac{\pi}{6}\)
Answer & Solution
Correct Answer
(D) \(\dfrac{\pi}{6}\)
Step-by-step Solution
Detailed explanation
The plane rises 1 m in every 2 m, so: \(\sin\theta = \dfrac{1}{2} \Rightarrow \theta = 30°\) When a body just slides down, it is at limiting equilibrium, so angle of friction \(\phi =\) angle of inclination \(\theta\). \(\phi = 30° = \dfrac{\pi}{6}\) radians
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